How to get difference in flask SQLalchemy queries then order the queries

Solution
combined = db.session.query(Ingredient).filter(Ingredient.ROrder.isnot(None)).\ 
    filter(_or(Ingredient.recipe_id==0, Ingredient.recipe_id==recipe_id)).\
    order_by(Ingredient.ROrder)
combined_objects = db.session.query(Ingredient).filter(Ingredient.ROrder.isnot(None)).\ 
    filter(_or(Ingredient.recipe_id==0, Ingredient.recipe_id==recipe_id)).\
    order_by(Ingredient.ROrder).all()

data_dict = {}
source_id_list = []

for combined_object in combined_objects:
    if combined_object.source_id not in data_dict.keys():
        # add to dictionary
        temp_dict = {'name': combined_object.name, 'Descriptor': combined_object.Descriptor,
             'tv': combined_object.tv, 'ROrder': combined_object.ROrder, 'recipe_id': combined_object.recipe_id}
        data_dict[combined_object.source_id] = temp_dict
        # keep track of list of source_ids
        source_id_list.append(combined_object.source_id)
    
    # if key is already in dictionary, check if recipe_id==recipe_id, if it does, overwrite data in dictionary
    else:
        if combined_object.recipe_id == recipe_id:
            # add to dictionary
            temp_dict = {'name': combined_object.name, 'Descriptor': combined_object.Descriptor,
                'tv': combined_object.tv, 'ROrder': combined_object.ROrder, 'recipe_id': combined_object.recipe_id}
            data_dict[combined_object.source_id] = temp_dict

# show result
for source_id in source_id_list:
    print(data_dict[source_id])